T 2 t 4 1 July 8, 2019 16 32 64 128 T 1 2 2t 1 4 1 0 T 4 t 2 1 0 T 1 )( t 2 2t 4 T 2 )= 4 t 15 T 2 1 t 4 1 integration 9 t 2 )= 4 t 15 T 3 2 t 12 4 3 t 2 )= 4 2t 1 2 t 4 10 T 2 4 11 Solve 3 t 2 )= 4 2t 1 X 2t 2 y t 4 1 Graph 17 * t 2 * t ** 4 T 2 3t 10 )( t 4 Integration of t 2 1 t 4 1 dt
