X 1 2 3 4 5 July 8, 2019 16 32 64 128 X 1 2 3 4 5 to infinity X 1 2 3 4 5 the number of different ordered pairs X 1 2 3 4 5 6 X 1 2 3 4 5 y X 1 2 3 4 5 8 X 1 2 3 4 5 0 Let x 1 2 3 4 5 1 2 3 x 4 5 6 7 8 1 2 3 x 4 5 as a fraction 1 2 x 3 4 )= 5 12 X 1 2 4 5x 3 Х 1 2 4 5х 3 X 1 2 5x 12 3 4 5х 4х 3х 2х х =- 1 2 3 4 5 Х 3 4 1 2 3 5
