X 2 dy 2xy dx 0 y =- 1 x 2 July 8, 2019 16 32 64 128 Y 2xy 1 dx x 1 2xy x 2y 2 dy 0 X y 2 dx 2xy x 2 − 1 dy 0 y 1 1 Y dx = 2(x + y) dy