X 2y 4 0 2
- X 2y 4 0 2x 4y 12
- X 2y 2z 4 0
- X 2y 4 3x 2y 0
- X 2y 4 x 2y 0
- X 2y 4 0 is a common tangent to y 2 4x
- X 2 y 2 4x 2y 4 0
- X 2y 7 0 2x y 4 0
- Solve graphically x 2y 4 0 2x y 3
- X 2y 4 0 2x 4y 12 0 by substitution method
- X 2y 4 0 2x 4y 12 0 by graphical method
- X 2y 4 0 2x 4y 12 0 by elimination method
- X 2y 0 2x 5y =- 4
- X 2y 0 2x y 4
- X 2y 4 0 and 2x 4y 12 0 represents
- X 2y 4 0 and 2x 4y 12 0 then the lines are