X 3 5 0 July 8, 2019 16 32 64 128 X 3 5 0 2 X 3 5 0 4 X 3 5 0 8 20 X3 x 5 0 X 3 2x 5 0 by regula falsi method X 3 )( 2x 5 )= 0 X 3 3x 5 0 X 3 4x 5 0 X 3 2x 5 0 using secant method X 3 6x 5 0 X 3 7x 5 0 3 x 0.5 5 10 x 3 5 0 X 3 9x 5 0 X 3 5x 5 0
