X 3 y 2x 5 July 8, 2019 16 32 64 128 X y 3 2x 5y 12 X 2y 3 y 2x 5 X 2y 3 2x 3y =- 5 3 x y 5 2x y 4 Y x 3 2x 5 4 derivative X 3 y 2x 5 1 1 3 X 3y 2x y 5 X 3 y 2 2x 5 y 3 X y 3 2x 3y 5 X 3y 1 y 2x 5 X y 3 2x 5y 12 by substitution method X y 3 2x 5y 12 by elimination method X y 3 2x 5y 12 graphically
