X 5y 3 2x y
- X 5y 3 x2 2xy y2 =- 1
- X y 3 2x 5y 12
- X y 3 2x 5y =- 21
- X 5y 3 y 2x 5
- X 3 5y 13 2x y 2 19
- X 3 5y 13 2x y 2 19 by substitution method
- X y 3 2x 5y 12 by substitution method
- X y 3 2x 5y 12 by elimination method
- X y 3 2x 5y 12 graphically
- X y 3 2x 5y 13 by substitution method
- X y 3 2x 5y 13 by elimination method
- X y 3 2x 5y 9
- 2x y 3 x 5y 40
- F x y )= 2x 5y 3