X 5y 4 2x 3y 1 July 8, 2019 16 32 64 128 2x 3y =- 4 x 5y 11 by substitution method X 1 5y =- 4 3y 2x 8 X 5y 11 2x 3y =- 4 by elimination method X 3y 4 2x 5y 12 2x 3y =- 4 x 5y 11 2x 3y 4 0 x 5y 11 2x 3y 4 0 x 5y 11 by substitution method 2x 3y 4 0 x 5y 1
