Y 2x 3 y 4x 5 July 8, 2019 16 32 64 128 4x y 3 2x 3y 5 2x y 3 4x y 5 by substitution method 2x y 3 0 4x y 5 0 2x y 3 0 4x y 5 0 by elimination method Solve y 2x 3 and y 4x 5 by substitution method 4x y 3 2x 3y 5 graph Y = 2x + 5 2x + y = 4
