Y 3 x 3y 5 July 8, 2019 16 32 64 128 X y 3 4x 3y 5 X 2 y 3 )( 2x 3 3y 5 2x y 3 x 3y 5 Y 3x 3y x 5 X 3y 5 0 2x y 3 0 2x y 3 x 3y 5 metode substitusi 2x y 3 x 3y 5 metode eliminasi Y 3 x 3y x 5 substitution method 2x y 3 dan x 3y 5 X 4 y 3 3y 5z vĂ xyz 100 Y 5 x 5x 3y 3