Y 4 )( 3y 5 )= 0 July 8, 2019 16 32 64 128 3y 4 1 y 0 5 1 6 y 2 )- 0 4 5 3y )=- 0 8 4y 2 2x 3y 4 0 3x y 5 0 2 3y 5 8 y 4 0 2x y 4 3x 2y 6 x 3y 5 0 16 y 3 )- 3y 4 y 5 )= 0 2x 3y 4 0 3x y 5 0 by substitution method 2x 3y 4 0 3x y 5 0 by graphical method 2x 3y 4 0 3x y 5 0 by elimination method
