Y 4 1 2 x 7 July 8, 2019 16 32 64 128 4 y 1 2 =- 7 x 3 1 2 y 4 )=( x 7 2 in vertex form Y x 4 2 2m 1 x 2 7 Y =- frac 1 4 x 2 + 6x 7 Which point is on the graph of y 4 1 2 x 7 Y 1 2 x 5 3 7 4 1 2 4 x 1 )- 2 y 0 5 )= 7 Y 3 x 1 2 2 75 4 in standard form Y = 2x + 1. y = negative 4 x + 7