Y 6 1 5 x 8 July 8, 2019 16 32 64 128 X 10 y 5 1 x 8 y 6 15 X =- 3 4 y 1 6 z 5 8 X 10 y 5 1 x 8 y 6 15 by elimination method X 10 y 5 1 x 8 y 6 15 by substitution method Xy 6
