Z 1 z 1 3 July 8, 2019 16 32 64 128 Lim z → 1 z 1 3 Arg z 1 z 1 )= pi 3 Z 1 3 z 1 2 Z 1 z 3 8 Z 1 )( z 3 )= 0 Z 2 1 5 z 3 1 4 Z 1 3 1 z 2 4 Z z 1 1 3z 3 Lim z tends to 1 z 1 3 Z 2 1 5 z 3 1 4 solve Inverse z transform of 1 /( z 1 3