2 5y 3 ) 4y =- 1 July 8, 2019 16 32 64 128 2 5y 3 )+ 4y =- 1 3 7y 2 5y 1 4y 3 38 5y 3 2 4y 12 5y 3 2 4y 12 answer 5y 3 4y 2 10y 8 5y 3 y )( 4y 1 2 0 (- 4y 3 5y 16 )+( 4y 2 y 9 4y 3 12y 2 5y 4y 3 5y 2 12y 15 Factor 2y 3 4y 2 5y 10 by grouping 4y 3 5y 2 8y 10 3 4y 1 )= 2 5y 1 2 solve for y 2 4 2y 1 )+ 5y 9 3 4y 7 16x 5y 2 16x 4y 3 4x 3y 4