3 5 0 6 1 July 8, 2019 16 32 64 128 5 0 6 1 3 2 0 3 5 6 1 4 5 0 10 6 3 5 0 6 1 5p )+ 8 3 5p 1 3 х 0 6 1 5 х 30 0 5x 6 1 5 3 5x 1 5 0 6 ∙ 2 3 П 6 3 4 0 5 1 3 0 6 x 3 5 1 4 Evaluate 5 0 6 1 3 2 3 x 12 5 =- 0 6 5 6 0 3 1 9 6 6 3 0 5 1 solution 5 0 6 1 4 and 8 3 4 Ds 1 6 3 0 5
