3 y 2 ) 4 2y 5 July 8, 2019 16 32 64 128 3 y 2 )+ 4 2y 5 2 3 y 3 4 2y 5 8 X y 2 4 x 3 2y 5 3 y 2 5 )= 6 9 4 2y Expand and simplify 3 y 2 )+ 4 2y 5 2x 3 y 2 4 x 2y 5 1 2y 1 3 y 2 4 =- 5 2 3y 2 )- 4 2y 5 )= 9 X y 2 4 x 3 2y 5 by substitution method X y 2 4 x 3 2y 5 by elimination method 2 y 3 )+ 5y 4 2y 3 )+ 8 Solve 3 2y 4 )+ 5y 2 y 7
