X 2 5 1 2 3 4 July 8, 2019 16 32 64 128 X 2 5 + 1 2 3 4 2 x 1 )- 5 2 3 4x )= 1 X 2 3 4 5 y 1 2 3 4 5 1 2 x 2 3 4 as a fraction 2 x 3 )/ 5 1 2 3x 4 4 5 2 x 2 3 4x 1 0 X 2 4x 5 2 x 1 x 3 4 3 5 8 x 2 1 2 x 4 as a fraction 2 9 x 2 1 3 2 3x 5 4 9x Solve for x 2 5 x − 1 2 )= − 2 3 4 3 2 x 2 1 5 3 4x8 25 3 x 2 )- 5 2x 1 )- 2 3x 4 )+ 10 0
